NEET Class neet Answered
An Astronomical Telescope Has Focal Lengths 100 & 10 Cm Of Objective And Eyepiece Lens Respectively When Final Image Is Formed At Least Distance Of Distinct Vision, Magnifying Power Of Telescope Will Be.
Asked by semboy65ks | 04 Jul, 2019, 05:40: PM
Expert Answer
Magnifying power of telescope = ( fo / fe ) = 100/10 = 10
fo is focal length of objective lens and fe is focal lengh of eyepiece lens.
Answered by Thiyagarajan K | 04 Jul, 2019, 07:54: PM
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