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CBSE Class 9 Answered

ABCD is a quadrilateral and BD is one of its diagonals as shown in the figure. DC= 5 cm, Altitude=10 cm. Show that ABCD is a parallelogram. Find its area.
Asked by Topperlearning User | 17 Aug, 2017, 12:18: PM
answered-by-expert Expert Answer
Diagonal BD intersects AB and CD such that
CDB = ABD = 90o
 AB  DC, and AB = DC = 5 units.
(One pair of sides of quadrilateral ABCD is equal and parallel.)                        
ABCD is a parallelogram
Area of parallelogram = base x corresponding altitude
                                    = 5 x 10 = 50 sq. units
Hence area of parallelogram = 50 sq. units
Answered by | 17 Aug, 2017, 02:18: PM

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