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A drop of mercury of radius 3 mm splits into 27 identical droplets. Find the increase in surface energy. Surface tension of mercury is 0.465 N/m.

Asked by Topperlearning User 1st August 2014, 4:23 PM
Answered by Expert
Answer:

Let r be the radius of the small droplet. As the volume of mercury will remain constant on splitting the drop into droplets, therefore

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Answered by Expert 1st August 2014, 6:23 PM
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