NEET Class neet Answered
A body starts from rest moving with a constant acc 2 m per sec square for 10 sec , then move with a constant velocity for next 10 sec. Finally ,move with uniform retardation 4 m per sec square for 8s. Find the distance travelled by the body
Asked by debabrata131ta | 30 Nov, 2019, 09:55: AM
Expert Answer
Distance travelled in accelerated motion, S1 = (1/2) a t2 = (1/2)×2×102 = 100 m
speed after 10 s = a t = 2×10 = 20 m/s
Distance travelled with uniform speed, S2 = v × t = 20 × 10 = 200 m
Distance travelled with retardation, S3 = u t - (1/2)at2 = [ ( 20 × 8 ) ] - [ (1/2) × 4 × 82 ] = 32 m
Total distance travelled = S1 + S2 + S3 = 100 + 200 + 32 = 332 m
Answered by Thiyagarajan K | 30 Nov, 2019, 05:06: PM
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