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A body is thrown up with an initial velocity u and covers a maximum height of h, then h is equal to

Asked by 29th December 2011, 12:00 AM
Answered by Expert
Answer:
we know , v2-u2=2as
s=H , v=0m/s and a=-g
 hence, -u2=-2gH
so, maximum height attained is
     H=u2/2g
Answered by Expert 29th December 2011, 10:41 PM
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