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CBSE Class 9 Answered

In circle ,ABC is an isosceles triangle with AB=AC and P is point on side AC.Through C a line is drawn to intersect BP produced in Q,such that angle ABQ=angle ACQ.
 
PROVE THAT :ANGLE AQC=90 DEGREE+1/2 OF ANGLE A.
 
 
Asked by ranjitrk1 | 14 Mar, 2016, 09:40: PM
answered-by-expert Expert Answer
begin mathsize 12px style In space isosceles space triangle space ABC comma space angle ABC equals fraction numerator 180 degree minus angle BAC over denominator 2 end fraction ABCQ space is space straight a space cyclic space quadrilateral. Hence comma space angle AQC equals 180 degree minus angle ABC equals 180 degree minus open parentheses fraction numerator 180 degree minus angle BAC over denominator 2 end fraction close parentheses equals 180 degree minus open parentheses 90 degree minus fraction numerator angle BAC over denominator 2 end fraction close parentheses equals 90 degree plus fraction numerator angle BAC over denominator 2 end fraction space left parenthesis Proved right parenthesis end style
Answered by satyajit samal | 15 Mar, 2016, 06:14: PM

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