JEE Class main Answered
Given least count 0.05 cm = 0.5 mm is unrealistic value.
( approximately we can measure 0.5 mm without vernier )
Normally main scale smallest division is 1 mm .
If vernier has 10 divisions , then least count is 0.1 mm = 0.01 cm
If vernier has 20 divisions , then least count is 0.05 mm = 0.005 cm .
Hence , it is assumed that least count of vernier is 0.005 cm
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If there are n divisions in vernier scale and n divisions of vernier scal coinicide with (n-1) divisions of main scale ,
then leasct count LC is
where MSD is 1 main scale division.
In given vernier Caliper , 1 cm is divided by 10 divisions.
MSD = 1 cm /10 = 0.1 cm
If n divisions of vernier coincide with (n-1) divisions of main scale divisions and leat count is 0.05 cm , then
from above expression, we get ,
n = 0.1/0.005 = 20