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0.80g of impure (NH4)2SO4 (mohr's salt) was boiled with 100 mL of 0.2N NaOH solution till all the NH3 gas evolved. The remaining solution was diluted to 250 mL. 25 mL of this solution was neutralized using 5mL of 0.2N H2SO4 solution. What is the percentage purity of the sample?
Asked by ntg432000 | 23 Mar, 2019, 09:28: PM
answered-by-expert Expert Answer
m i l l i e q u i v a l e n t space o f space H subscript 2 S O subscript 4 equals space 5 cross times 0.2 space equals space 1 M i l l i e q. space o f space R e m a i n i n g space N a O H space space s o l u t i o n space equals space 1 M i l l l i e q. space O f space N a O H space r e a c t i n g space w i t h space s a l t space equals space 100 cross times 0.2 space minus 10 space equals space 10 S o comma space W subscript P u r e space s a m p l e end subscript over E space cross times space 1000 space equals space 10 S o comma space W subscript P u r e space s a m p l e end subscript space equals space fraction numerator 10 cross times 66 over denominator 1000 end fraction space equals space 0.66 percent sign space p u r i t y space equals space fraction numerator 0.66 cross times 100 over denominator 0.8 end fraction space equals space 82.5 space percent sign
Answered by Sumit Chakrapani | 26 Mar, 2019, 01:58: PM

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