CBSE Class 10 Answered
zeroes of the quadratic polynomial p(x)=x^2+3x-(a+2)(a-1) are
Asked by jytingale | 29 Jul, 2020, 01:09: PM
Expert Answer
The given polynomial is: P(x)=x2+3x-(a+2)(a-1)
Zeros of the polynomial obtained by taking P(x)=0
x2+3x-(a+2)(a-1)=0
x2 + (a+2)x - (a-1)x - (a+2)(a-1) = 0
x[x+a+2] - (a-1)[x+a+2]=0
[x+a+2][x - (a-1)] = 0
x=-(a+2) or x=a-1
Hence, the zeros of the polynomial are (a+2) and (a-1).
Answered by Renu Varma | 30 Jul, 2020, 12:27: PM
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