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xy=ex-y find dy/dx
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Asked by namithnandan838 | 03 Mar, 2024, 08:16: PM
answered-by-expert Expert Answer

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By taking logarithm on both sides , we get

ln(x y ) = ( x - y)

ln(x)+ln(y) = x - y

if we differentiate above expression on bothe sides , we get

(1/x ) + (1/y) (dy/dx) = 1 - (dy/dx)

(dy/dx) [ (1/y)+1 ] = 1 - (1/x)

dy/dx = (y/x) [ (x-1)/(y+1) ]

Answered by Thiyagarajan K | 03 Mar, 2024, 09:27: PM
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hi
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