Why are low spin tetrahedral compounds not formed?
Asked by Navya Benny | 8th Jan, 2016, 12:44: PM
- There are only 4 ligands in a tetrahedral complex.
- So, the ligand field is roughly 2/3 of the octahedral field.
- The direction of ligand approach in tetrahedral complex does not coincide with the d-orbitals.
- This reduces the field by a factor of 2/3. Hence, ∆t is roughly 2/3 x 2/3 = 4/9 of ∆o.
- As a result, all tetrahedral complexes are high-spin since the CFSE is normally smaller than the paring energy.
Answered by Prachi Sawant | 8th Jan, 2016, 04:39: PM
- why is [Fe(CN)6]3− a low spin complex even though it has a free electron?
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- A. If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion. B. If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion. C. If Assertion is True but the Reason is False. D. If both Assertion & Reason are False. Assertion :- The dFe–O[In[Fe(H2O)6]3+] < dFe–O[In[Fe(H2O)6]2+]. Reason :- 'H2O' is a π acid ligand.
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