WHICH TERM OF THE SEQUENCE 20,77/4, 37/2,71/4.......IS THE FIRST NEGATIVE TERM?
Asked by
| 6th Feb, 2014,
12:24: PM
Expert Answer:
Dear Student,
20,
,
,
2nd term - 1st term =
- 20 =
-
=
.
3rd term - 2nd term =
-
=
-
=
.
4th term - 3rd term =
-
=
-
=
.
So the common difference is d = 
Use the nth term formula for an arithmetic sequence.
an = a1 + (n-1)d
1st term = a1 = 20, d =
an = 20 + (n-1)
We set that < 0 to make it negative, and solve for n:
20 + (n-1)
< 0
Multiply both sides by 4
80 + (n-1)(-3) < 0
80 + (-3)(n-1) < 0
80 - 3(n-1) < 0
80 - 3n + 3 < 0
83 - 3n < 0
-3n < -83
n >
So the 28th term is the first negative term.
That term is:
an = a1 + (n-1)d
a28 = 20 + (28-1)
a28 = 20 + (27)
a28 = 20 +
a28 =
-
a28 = 
Dear Student,
20,
,
,
2nd term - 1st term =
- 20 =
-
=
.
3rd term - 2nd term =
-
=
-
=
.
4th term - 3rd term =
-
=
-
=
.
So the common difference is d = 
Use the nth term formula for an arithmetic sequence. an = a1 + (n-1)d 1st term = a1 = 20, d =
an = 20 + (n-1)
We set that < 0 to make it negative, and solve for n: 20 + (n-1)
< 0 Multiply both sides by 4 80 + (n-1)(-3) < 0 80 + (-3)(n-1) < 0 80 - 3(n-1) < 0 80 - 3n + 3 < 0 83 - 3n < 0 -3n < -83 n >
So the 28th term is the first negative term. That term is: an = a1 + (n-1)d a28 = 20 + (28-1)
a28 = 20 + (27)
a28 = 20 +
a28 =
-
a28 =
Answered by
| 6th Feb, 2014,
03:12: PM
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