What would be the steps of construction to divide a line segment in the ratio of 5 : 8 ?
Asked by ayushmukul | 30th Oct, 2009, 06:22: PM
Steps of construction:
1. Draw a ray AX making an acute angle with AB.
2. Locate 13 (5+8) points A1, A2.......A13 on AX so that AA1 = A1A2= A2A3.......= A12A13
3. Join BA13
4. Through the point A5, draw a line parallel to A13B intersecting AB at point C. Then AC : CB = 5 : 8
Answered by | 4th Nov, 2009, 04:26: PM
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