What is the probability of having 53 Thursdays in a leap year?
Asked by Topperlearning User | 4th Apr, 2014, 10:52: AM
In a leap year, there are 366 days.
52 weeks = 364 days
1 leap year = 52 weeks and 2 days
These extra two days can be sun-mon, mon-tue, tue-wed, wed-thu, thu-fir, fri-sat, sat-sun.
Total number of outcomes = 7
Number of favorable outcomes = 2
P(53 Thursdays) =
Answered by | 4th Apr, 2014, 12:52: PM
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