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# CBSE Class 10 Answered

Verify the relationship between zeroes and coefficients of the cubic polynomial p(x) = 3x^{3} - 5x^{2} - 11x - 3p(x)=3x3−5x2−11x−3.
Asked by bibhudeepanp | 01 Jul, 2021, 10:03: PM Expert Answer
P(x) = 3 x3 - 5 x2 -11 x -3   ............................. (1)

If we put x = -1 , we get P(-1) = 0

Hence (x+1) is a factor of P(x)

After dividing P(x) by (x+1) , we get , P(x) = (x+1) ( 3x2 -8x -3 )

After factorising ( 3x-8x -3 ) , we get,  P(x) = (x+1) (x-3)(3x+1)

Cubic polynomial with zeros of polynomials as -a, -b and -c is given as

(x+a) (x+b) ( x+c) = x3 + ( a +b +c )x2 + ( ab + bc + ca ) x + (abc) ......................(2)

Given polynomial P(x) can be written in terms of factors as

P(x) = (1/3) ( x+1) ( x-3 ) [ x + (1/3) ] = (1/3) [ x3 - (5/3)x2 -(11/3)x -1 ] ..................(3)

we get from the factors of polynomial ,  a = 1  , b = -3  and c = (1/3)

By comparing eqn.(2) and (3) , we should get , a+b+c = -5/3 . This can be verified by substituting values of a, b and c

Similarly ( ab+bc+ca ) = -5/3 . This can be verified by substituting values of a, b and c

Similarly  ( a b c ) = 1 × (-3) × (1/3) = -1

Answered by Thiyagarajan K | 18 Sep, 2021, 03:49: PM

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