variation of 'g' with height

Asked by raghavendran7 | 2nd Dec, 2009, 08:28: PM

Expert Answer:

gh = GM/(R+h)2

g at the earth surface, h = 0.

gs = GM/R2

gh = GM/(R+h)2 = 0.25gs

1/(R+h)2 = 0.25/R2

4R2 = R2 + 2Rh + h2

2Rh + h2 - 3R2 = 0

h = [-2R±(4R2+12R2)1/2]/2

So h = R

The value of g becomes 25% of its value on the surface of earth, at a height equal to the radius of the earth i.e. 6400 km.

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Answered by  | 2nd Dec, 2009, 08:41: PM

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