CBSE Class 12-science Answered
using gauss's law derive an expression for electric field intensity long, straight line of linear charge density ø per cm.
Asked by Balan | 26 Mar, 2018, 01:39: PM
Expert Answer
Let us imagine a surface of cylinder symmetrically placed so that its axis coincides with the charged line as shown in figure. Let r be the radius of cylinder and l be its length. Very near to the charged line field lines are perpendicular to the charged line and no field lines are passing through the cross section of cylinder. There is a uniform electric field on the surface of cylinder.
As per Gauss law 
...................(1)
...................(1)Equation (1) can be written as E×2 π r×l = ( λ l ) / εo
Hence 
Answered by Thiyagarajan K | 26 Mar, 2018, 08:43: PM
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