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CBSE Class 12-science Answered

an object 2cm high is placed at a distance of 16cm from a concave mirror which produces a virtual image 3cm high what is the focal length of the mirror ?
Asked by pushpamagadum21 | 09 Jul, 2024, 20:43: PM
answered-by-expert Expert Answer

Magnification m of image formed by concave mirror is

m = - v / u = (  hi / ho )

where v is mirror-to-image distance and u is mirror-to-object distance .

where h= 3 cm is height of image and h=  2 cm is height of object .

Since image is virtual both heights of object and image are positive .

Hence magnification m is 

m = - v/u = 3/2 = 1.5

Mirror-to-object distance u =  -16 cm ( Cartesian sign convention is followed )

Hence mirror-to-image distance is

v = 16 × 1.5 = 24 cm

Focal length f is calculated from mirror equation

( 1/v ) + ( 1/u ) = 1/f

1/f = ( 1/24 ) - ( 1/16) = -1/48

Hence focal length of concave mirror = - 48 cm

( Focal length of concave mirror is negative by Cartesian sign convention )

 

 

Answered by Thiyagarajan K | 09 Jul, 2024, 22:55: PM
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