CBSE Class 10 Answered
urgent!!!plz answer as soon as possible
Asked by honey_physics | 14 Feb, 2010, 11:35: AM
Expert Answer
AEB and AED are right anlged triangles, with AEB = AED = 90 ....Diagonals intersect at right angles.
AE2 + EB2 = AB2
AE2 + ED2 = AD2 ...........Pythagorus's theorem.
Similarly for CEB and CED
CE2 + EB2 = BC2
CE2 + ED2 = CD2 ...........Pythagorus's theorem.
Adding all four equation,
AE2 + EB2 + AE2 + ED2 + CE2 + EB2 + CE2 + ED2 = AB2+BC2+CD2+AD2 ...........(1)
Now,
AC2 = (AE+EC)2 = AE2+EC2+2AEEC = AE2+EC2+2AE2 ....................Diagonals bisect each other.
= AE2 + EC2+ AE2 +EC2 ........writing out 2AE2 = AE2 + AE2 = AE2 + EC2
Similarly,
BD2 = BE2 + ED2 + BE2 + ED2
Using this result in (1).
AC2 + BD2 = AB2+BC2+CD2+AD2
Regards,
Team,
TopperLearning.
Answered by | 14 Feb, 2010, 12:31: PM
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