CBSE Class 12-science Answered
Two rings each of mass M-100 gm are constrained to move along a fixed horizontal rod An ideal string is connected with rings and block of mass M, = 200 gm is connected to the mid point of string At a certain moment the mass m is moving downward with velocity ?3 m/s. Find the speed of ring of M at the moment:
M
2m
2m
M
30°
30°
Molvo = ?3 m/s
Asked by 11soumya09 | 29 Sep, 2023, 19:35: PM
![](https://images.topperlearning.com/topper/tinymce/imagemanager/files/f85cc8bc1c3562b482f7f88ed52b7dec6516e4d8a88767.08370024f3.png)
Let l be the semi-length between rings and h be the distance between mass and rod as shown in figure.
when the mass is always at centre of string, then we have
![begin mathsize 14px style l squared space plus space h squared space equals space c o n s tan t end style](https://images.topperlearning.com/topper/tinymce/cache/932df1290e37b3eb537a83d71aad7ab1.png)
if we differentiate above eqn.(1) , then we get
![begin mathsize 14px style 2 space l space fraction numerator d l over denominator d t end fraction plus space 2 space h space fraction numerator d h over denominator d t end fraction space equals space 0 end style](https://images.topperlearning.com/topper/tinymce/cache/d84a4c0e623b5ae533c86e8cc2cf6ded.png)
where dl/dt is speed of ring and dh/dt is speed of mass .
Then from above expression, we get
![begin mathsize 14px style fraction numerator d l over denominator d t end fraction equals space minus h over l cross times fraction numerator d h over denominator d t end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/12785e8045bd82cbca96da403590bf81.png)
Answered by Thiyagarajan K | 29 Sep, 2023, 20:32: PM
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