Two events A and B are such that P open parentheses top enclose A close parentheses equals 0.3 comma space P left parenthesis B right parenthesis equals 0.4 space comma space P left parenthesis A intersection top enclose B right parenthesis equals 0.5. space F i n d space v a l u e space o f space P left parenthesis B divided by top enclose A intersection top enclose B right parenthesis.

Asked by Aswin | 6th Jan, 2016, 04:28: PM

Expert Answer:

straight P left parenthesis straight B divided by top enclose straight A intersection top enclose straight B right parenthesis equals fraction numerator straight P open parentheses straight B intersection top enclose straight A intersection top enclose straight B close parentheses over denominator straight P open parentheses top enclose straight A intersection top enclose straight B close parentheses end fraction equals fraction numerator straight P open parentheses top enclose straight A intersection straight B intersection top enclose straight B close parentheses over denominator straight P open parentheses top enclose straight A intersection top enclose straight B close parentheses end fraction equals fraction numerator straight P open parentheses top enclose straight A intersection straight ϕ close parentheses over denominator straight P open parentheses top enclose straight A intersection top enclose straight B close parentheses end fraction equals fraction numerator straight P open parentheses straight ϕ close parentheses over denominator straight P open parentheses top enclose straight A intersection top enclose straight B close parentheses end fraction equals fraction numerator 0 over denominator straight P open parentheses top enclose straight A intersection top enclose straight B close parentheses end fraction equals 0

Answered by Vijaykumar Wani | 7th Jan, 2016, 01:02: PM

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