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Two cars A and B leave Mumbai at the same time, travelling in opposite directions. If the average speed of car A is 8 km/h more than that of B and they are 300 km apart at the end of 6 hrs, what is the average car A
Asked by brakishorkumar718 | 01 Jun, 2020, 11:00: AM
Let the average speed of the car B be x km/hr
Average speed of the car A will be (x+8) km/hr
After 6 hours, cars A and B are 300 km apart from each other.
After 6 hours, distance travelled by car A would be 6(x+8) and that of by B would be 6x.
Therefore, 6(x+8)+6x=300
6x+48+6x = 300
12x+48 = 300
12x = 252
x = 21
Hence, the average speed of B is 21 km/hr and that of A is x+8 = 29 km/hr.
Answered by Renu Varma | 01 Jun, 2020, 12:48: PM

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