Request a call back

# CBSE Class 10 Answered

trigonometry
Asked by akhileshnarayanan | 12 Mar, 2010, 02:27: PM

 Class Class mark Frequency Cumulative Frequency 0-10 5 8 8 10-20 15 8 16 20-30 25 14 30 30-40 35 22 52 40-50 45 30 82 50-60 55 8 90 60-70 65 10 100

Mean = (5x8 + 15x8 + 25x14 + 35x22 + 45x30 + 55x8 + 65x10)/100 =  37.2

n/2 = 100/2 = 50, hence median class is 30-40, l = 30, cf = 30, f = 22, h = 10.

Therefore, median = 30 + (50-30)x10/22 = 39.09

Modal class, 40-50. Hence, f0 = 22, f1 = 30, f2 = 8, l = 40, h = 10.

Mode = 40 + ((30-22)/(2x30-22-8))x10 = 42.67.

Regards,

Team,

TopperLearning.

Answered by | 14 Mar, 2010, 08:15: AM
CBSE 10 - Maths
Asked by akhilrallabandi08 | 19 Sep, 2021, 06:52: PM
CBSE 10 - Maths
Asked by shashwatpns | 22 Apr, 2010, 04:58: PM
CBSE 10 - Maths
Asked by RACHIT_MAHAAN | 15 Mar, 2010, 02:48: PM
CBSE 10 - Maths
Asked by kirtichawla94 | 12 Mar, 2010, 03:50: PM
CBSE 10 - Maths
Asked by akhileshnarayanan | 12 Mar, 2010, 02:27: PM
CBSE 10 - Maths
Asked by ashwinivg | 10 Mar, 2010, 08:46: PM