CBSE Class 10 Answered
trigonometry
Asked by akhileshnarayanan | 12 Mar, 2010, 02:27: PM
Expert Answer
|
Class |
Class mark |
Frequency |
Cumulative Frequency |
|
0-10 |
5 |
8 |
8 |
|
10-20 |
15 |
8 |
16 |
|
20-30 |
25 |
14 |
30 |
|
30-40 |
35 |
22 |
52 |
|
40-50 |
45 |
30 |
82 |
|
50-60 |
55 |
8 |
90 |
|
60-70 |
65 |
10 |
100 |
Mean = (5x8 + 15x8 + 25x14 + 35x22 + 45x30 + 55x8 + 65x10)/100 = 37.2
n/2 = 100/2 = 50, hence median class is 30-40, l = 30, cf = 30, f = 22, h = 10.
Therefore, median = 30 + (50-30)x10/22 = 39.09
Modal class, 40-50. Hence, f0 = 22, f1 = 30, f2 = 8, l = 40, h = 10.
Mode = 40 + ((30-22)/(2x30-22-8))x10 = 42.67.
Regards,
Team,
TopperLearning.
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