CBSE Class 10 Answered
Triangles Proof Problem!
Asked by RACHIT_MAHAAN | 30 Dec, 2009, 01:07: PM
Expert Answer
the quadrilateral ABDC is a cyclic quadrilateral as one pair of opp angles is supplementary.
so PDB being the exterior angle of the cyclic quadrilateral is equal to the interior opp angle i.e. angel BAC.
now, consider triangles PDB and PAC,
angle P = angle P ... common
angle PDB=angle PAC.. proved before since PAC is the same angle BAC
so, the two triangles are similar by AA rule.
so
PD/PA=PB/PC.. corr sides of similar triangles are proportional.
so
PA.PB=PC.PD
Note : the result must be as shown in bold letters.
Answered by | 30 Dec, 2009, 06:52: PM
CBSE 10 - Maths
Asked by s.sreeram | 11 Mar, 2010, 08:14: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:08: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:05: PM
ANSWERED BY EXPERT