triangle
Asked by suchet_r | 30th Aug, 2009, 08:03: PM
Let ΔPQR be the right angled triangle, and PQR = 90,
Area of an equilateral triangle = 3x(Side)2/4
The area of equilateral triangle on side PQ = 3xPQ2/4
The area of equilateral triangle on side QR = 3xQR2/4
The area of equilateral triangle on side PR = 3xPR2/4
Using Pythagoras' Theorem,
PR2 = PQ2 + QR2,
Multiplying both sides by 3/4
(3/4)PR2 = (
3/4)PQ2 + (
3/4)QR2,
Area of E. triangle on hypotenuse, PR = Area of E. triangle on side PQ + Area of E. triangle on side QR ]
Regards,
Team,
TopperLearning.
Answered by | 31st Aug, 2009, 01:03: AM
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