Transverse common tangent
Asked by SSHHII | 13th Oct, 2009, 10:59: PM
If we form the triangle having sides as the line joining centres of the circle of length d, radius of the bigger circle from the point of tangency and the line parallel to the transverse tangent joining centre of smaller circle and perpendicular on the radius of the biggger circle. This line will be equal in length to the tranverse tangent let it be X.
The sides will be d, R+r, the length of tangent.
also this triangle forms a right angled triangle whose hypotnuse is d.
Thus applying Pythagoras theorem
Thus length of the transverse tangent = d2-(R+r)2
Answered by | 21st Oct, 2009, 06:02: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number