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Three mangoes and three apples are in box. If two fruits are chosen at random, the probability that one is a mango and the other is an apple is (a) 2/3 (b) 3/5 (c) 1/3 (d) None of these
Asked by anushkarajwar | 24 Mar, 2024, 01:19: PM

Let E1 be the event of selecting first time mango and selecting apple next time .

Let E2 be the event of selecting first time apple and selecting mango next time .

probability of event E1 is

p(E1) = (3/6 ) (3/5) = 3/10

probability of event E2 is

p(E2) = (3/6) (3/5 ) = 3/10

Hence two fruits are selected randomly one at a time , probability p of getting one mango and one apple is

p = p(E1)  + p(E2) = (3/10) + (3/10) = 3/5

Answered by Thiyagarajan K | 24 Mar, 2024, 02:52: PM
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