The sum of three numbers is 27 and their product is 405.Find the numbers. The numbers are in AP.

Asked by  | 26th Feb, 2012, 04:58: PM

Expert Answer:

Let the 3 numbers in AP be a-d,a,a+d.

given that : a-d+a+a+d=27

or, 3a=27

or, a=9



or, 9(9-d)(9+d)=405

or, 9(81-d2)=405

or, d2=36

or, d=+-(6)

Now when d=+6, the numbers are 3,9,15

And when d=-6 the numbers are 15,9,3

Answered by  | 26th Feb, 2012, 10:17: PM

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