CBSE Class 10 Answered
The sum of three numbers is 27 and their product is 405.Find the numbers.
The numbers are in AP.
Asked by | 26 Feb, 2012, 04:58: PM
Expert Answer
Let the 3 numbers in AP be a-d,a,a+d.
given that : a-d+a+a+d=27
or, 3a=27
or, a=9
Also
a(a-d)(a+d)=405
or, 9(9-d)(9+d)=405
or, 9(81-d2)=405
or, d2=36
or, d=+-(6)
Now when d=+6, the numbers are 3,9,15
And when d=-6 the numbers are 15,9,3
given that : a-d+a+a+d=27
or, 3a=27
or, a=9
Also
a(a-d)(a+d)=405
or, 9(9-d)(9+d)=405
or, 9(81-d2)=405
or, d2=36
or, d=+-(6)
Now when d=+6, the numbers are 3,9,15
And when d=-6 the numbers are 15,9,3
Answered by | 26 Feb, 2012, 10:17: PM
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