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<div> <p class="MsoNormal"><span style="font-size: 14.0pt; mso-bidi-font-size: 11.0pt; line-height: 115%;">The radius of the circle passing through the two foci and an end point of the minor axis of the ellipse&nbsp; x <sup>2</sup>/16 + y <sup>2</sup>/25 =1 is ?</span></p> </div>
Asked by Malavika Umesh | 01 May, 2015, 01:52: PM
For the ellipse , the major axis is along Y-axis and the minor axis is along X-axis. (since the denominator of x2 term is less)
Here
The coordinates of foci are
The end points of minor axis are
So, we have to form a circle passing through  and one end point of minor axis .
Since, it's an isosceles triangle, the center lies on the perpendicular bisector of , that is X-axis.
Let the coordinates of the center be .
Equating the square of radii of the circle we get

Answered by satyajit samal | 03 May, 2015, 10:43: AM

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