The Position -time relation of a moving particle is given as x= 2t2+3t+4 (where x is in m and t is in s) what will be the velocity of the particle at t=1s ?

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The Position -time relation of a moving particle is given as x= 2t2+3t+4 (where x is in m and t is in s) what will be the velocity of the particle at t=1s ?

Asked by debankurmabdal11 | 20 Jun, 2020, 10:00: AM

Expert Answer

v equals fraction numerator d x over denominator d t end fraction x equals 2 t squared plus 3 t plus 4 v equals fraction numerator d x over denominator d t end fraction equals 4 t plus 3 a t space t equals 1 v equals 4 open parentheses 1 close parentheses plus 3 v equals 7 m divided by s

Answered by Utkarsh Lokhande | 20 Jun, 2020, 09:42: PM

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