NEET Class neet Answered
The motion of particle is along
Asked by Prashant DIGHE | 10 Jul, 2019, 04:11: PM
Expert Answer
x coordinate : x = 2+2t + 4t2 ; x-component of velocity = dx/dt = 2 + 8 t .......................(1)
y coordinate : x = 4t + 8t2 ; y-component of velocity = dy/dt = 4 +16 t .......................(2)
hence by dividing eqn.(2) by eqn.(1), we get, dy/dx = 2
since slope of x-y graph ( both x and y are displacement ) is constant, particle moves in a straight line
Answered by Thiyagarajan K | 10 Jul, 2019, 05:05: PM
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