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The mean output of a group of 50 workers was found to be 240 article. Afterwards it was detected that the output of one worker was wrongly recorded as 320 instead of 230 find the corrected value of mean output
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Asked by lokeshshah0404 | 09 Nov, 2021, 02:40: PM
answered-by-expert Expert Answer
mean space equals space fraction numerator total space articles over denominator total space workers end fraction 240 equals fraction numerator total space articles over denominator 50 end fraction total space articles space equals space 12000 correction colon total space articles space equals space 12000 minus 320 plus 230 space equals space 11910 new space mean space equals space 11910 over 50 equals 238.2
Answered by Arun | 10 Nov, 2021, 11:04: AM

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The mean output of a group of 50 workers was found to be 240 article. Afterwards it was detected that the output of one worker was wrongly recorded as 320 instead of 230 find the corrected value of mean output
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Asked by lokeshshah0404 | 09 Nov, 2021, 02:40: PM
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