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The ionization enery of HE+ is 19.6*10-18 J/ion.Calculate the enery of the first stationary state of Li2+.
Asked by mahadev2471 | 08 Jun, 2019, 11:51: AM
Given:
Ionisation energy of He+ = 19.6 × 10−18 J/ion
![Energy space of space the space first space orbit space of space Li to the power of 2 to the power of plus end exponent space
open parentheses straight E subscript He to the power of plus end subscript close parentheses subscript 1 space equals space minus straight Z squared subscript He
open parentheses straight E subscript Li to the power of 2 plus end exponent end subscript close parentheses subscript 1 space space space space end subscript equals space minus straight Z squared subscript Li
open parentheses straight E subscript Li to the power of plus end subscript close parentheses subscript 1 space space space space end subscript equals straight Z squared subscript Li over straight Z squared subscript He open parentheses straight E subscript He to the power of plus end subscript close parentheses subscript 1 space
space space space space space space space space space space space space equals open parentheses 3 close parentheses cubed over open parentheses 2 close parentheses squared cross times 19.6 cross times 10 to the power of negative 18 end exponent
space space space space space space space space space space space equals space 44.1 cross times space cross times 10 to the power of negative 18 end exponent space straight J divided by ion](https://images.topperlearning.com/topper/tinymce/cache/4b5f707ab121bd625587de865367f3a9.png)
The enery of the first stationary state of Li2+ is 44.1× 10-18 J/ion
Answered by Varsha | 08 Jun, 2019, 22:12: PM
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