ICSE Class 6 Answered
The handle of a water pump is 90 cm long from its piston rod. If the pivot handle is at a distance of 15 cm from the piston rod, calculate (a) least effort required at its other end to overcome a resistance of 60 kgf and (b) mechanical advantage of handle.
Asked by ploganathan9 | 18 Dec, 2019, 07:45: PM
Expert Answer
Let's first calculate mechanical advantage.
Load arm =15 cm
Effort arm = handle of water pump - load arm = 90 - 15 = 75 cm
MA = Effort arm/load arm = 75/15 = 5
Thus, effort required to overcome resistance or load of 60 kgf is,
MA = Load/Effort
Thus,
Effort = load/ MA = 60 kgf/5 = 12 kgf
Thus, effort = 12 kgf
Answered by Shiwani Sawant | 19 Dec, 2019, 11:01: AM
ICSE 6 - Physics
Asked by kushagramishra2aug2009 | 08 Apr, 2021, 10:11: AM
ANSWERED BY EXPERTICSE 6 - Physics
Asked by ritik16101 | 27 Jan, 2021, 11:42: AM
ANSWERED BY EXPERTICSE 6 - Physics
Asked by yashasvishukla17mar2009 | 05 Dec, 2020, 08:47: AM
ANSWERED BY EXPERTICSE 6 - Physics
Asked by ananyagupta14jun2009 | 01 Dec, 2020, 08:11: AM
ANSWERED BY EXPERTICSE 6 - Physics
Asked by aaryakhotele55.6spicertl | 24 Jul, 2020, 05:25: PM
ANSWERED BY EXPERTICSE 6 - Physics
Asked by pranatibhatt4891.6sdatl | 20 Jun, 2020, 12:16: PM
ANSWERED BY EXPERTICSE 6 - Physics
Asked by tarayadav6208 | 03 Jan, 2020, 10:54: PM
ANSWERED BY EXPERTICSE 6 - Physics
Asked by ploganathan9 | 18 Dec, 2019, 07:45: PM
ANSWERED BY EXPERTICSE 6 - Physics
Asked by mamtasalecha | 22 Oct, 2019, 08:30: PM
ANSWERED BY EXPERTICSE 6 - Physics
Asked by Purvi.nilay123 | 16 Oct, 2019, 10:34: PM
ANSWERED BY EXPERT
