ICSE Class 6 Answered
The handle of a nutcracker is 18 cm long & a nut is placed 2 cm from its hinge. If a force of 36 kgf is placed on the nut, it will crack. Calculate the force which has to be applied at the end of the handle to crack the nut.
Asked by banerjeeshipra.shipra | 07 Feb, 2019, 07:31: PM
Expert Answer
Load = 36 kgf
Load arm = 2 cm
Effort = ?
Effort arm =18 cm
Load x load arm = Effort x Effort arm
36 kgf x 2 cm = Effort x 18 cm
Effort = 4 kgf
Thus, to crack the nut the force of 4kgf must be applied at the end of the handle.
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