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the emf of a battery by a length of 80 cm on a potentiometer wire
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Asked by mdhanush411 | 07 Jan, 2021, 06:59: AM
answered-by-expert Expert Answer
Potential difference across A and B is given as,  VAB = VAC + VCD + VDE + VEB
 
where VAC = 2 V , potential difference across A and C ,
 
VCD = 1 A × 2 Ω  = 2 V , potential difference across C and D ,
 
VDE = -5 V , potential difference across D and E ,
 
VEB = 1 A × 1 Ω  = 1 V , potential difference across E and B 
 
VAB = VAC + VCD + VDE + VEB = ( 2 + 2 -5 +1 ) = 0 V
Answered by Thiyagarajan K | 07 Jan, 2021, 09:07: AM

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