NEET Class neet Answered
the emf of a battery by a length of 80 cm on a potentiometer wire
Asked by mdhanush411 | 07 Jan, 2021, 06:59: AM
Expert Answer
Potential difference across A and B is given as, VAB = VAC + VCD + VDE + VEB
where VAC = 2 V , potential difference across A and C ,
VCD = 1 A × 2 Ω = 2 V , potential difference across C and D ,
VDE = -5 V , potential difference across D and E ,
VEB = 1 A × 1 Ω = 1 V , potential difference across E and B
VAB = VAC + VCD + VDE + VEB = ( 2 + 2 -5 +1 ) = 0 V
Answered by Thiyagarajan K | 07 Jan, 2021, 09:07: AM
Application Videos
-
Growth of Current in L-R Circuit
In this video, the growth of current in RL circuit is explained. It include...
NEET neet - Physics
Asked by hardikmittal25 | 03 May, 2024, 02:57: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sa1033278 | 02 May, 2024, 07:37: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by bidyutpravarout79 | 26 Apr, 2024, 09:40: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by ramanjaneyuluoguru | 25 Apr, 2024, 04:18: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by shatakshibhatt9 | 20 Apr, 2024, 07:52: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by praveenpriya000079 | 18 Apr, 2024, 07:24: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by gouranshi84 | 17 Apr, 2024, 05:23: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sojusvi | 17 Apr, 2024, 01:12: PM
ANSWERED BY EXPERT
