Request a call back

The electric field E due to any point charge near it is defind E=lim f/q where q is the test charge. what is the physical significance of taking limit tends to zero in this expression ? Draw the electric field lines of point charge when Q>0 and Q<0.
Asked by aksingh8080 | 04 Jul, 2018, 09:32: PM
When there is a charge or charge distribution in a given region,
test charge q placed at some point in the given region experiences the electrostatic forceas per coulomb's law.
This force divideded by test charge (force per unit charge) is defiened as the electrical field at this point.
But this test charge should not alter the true field due to it's own charge. This is possible if test charge has
high magnitude of charge. Hence electric field is measured by a small magnitude of test charge (q → 0).

Field lines for point charge q, for both the sighs,  are shown in the figure given below

Answered by Thiyagarajan K | 05 Jul, 2018, 09:33: AM

## Concept Videos

CBSE 12-science - Physics
Asked by goswamideepak16492 | 12 Jun, 2024, 10:18: AM
CBSE 12-science - Physics
CBSE 12-science - Physics
Asked by rahuldevgayen4 | 10 Jun, 2024, 02:58: PM
CBSE 12-science - Physics
Asked by yy8965818 | 07 Jun, 2024, 08:36: PM
CBSE 12-science - Physics
Asked by vaidehi262008 | 05 Jun, 2024, 10:09: PM
CBSE 12-science - Physics