CBSE Class 10 Answered
Sushant has a vessel, of the form of an inverted cone, open at the top, of height 11 cm and
radius of top as 2.5 cm and is full of water. Metallic spherical balls each of diameter 0.5 cm are
put in the vessel due to which 25th of the water in the vessel flows out. Find how many balls
were put in the vessel. Sushant made the arrangement so that the water that flows out irrigates
the flower beds. What value has been shown by Sushant?
Asked by riyamaths | 15 Oct, 2018, 20:18: PM
According to teh question,
h = 11 cm, Radius of a conical vessel = r = 2.5 cm
radius of a metallic spherical ball = R = 0.5/2 = 0.25 cm
Let n be the number of spherical balls that were dropped in the vessel.
Volume of water spilled = Volume of spherical balls dropped
![begin mathsize 16px style 2 over 5 volume space of space cone equals straight n cross times volume space of space spherical space ball
fraction numerator begin display style 2 end style over denominator begin display style 5 end style end fraction cross times 1 third πr squared straight h equals straight n cross times fraction numerator begin display style 4 end style over denominator begin display style 3 end style end fraction πR cubed
solving space it space we space get
straight n equals 440.
Hence comma space the space number space of space spherical space balls space that space were space dropped space in space the space vessel space is space 440.
Sushant space has space made space such space an space arrangement space so space that space the space water space that space flows space out comma space irrigates space the space flower space beds. space
It space is space judicious space usage space of space water. end style](https://images.topperlearning.com/topper/tinymce/cache/37dbc0847e414a5afc634dd3261b20ea.png)
Answered by Sneha shidid | 22 Oct, 2018, 10:48: AM
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