Request a call back

Suppose i am hanging on the gym bar. The force on the bar is only my weight other than its own weight. Now if I try to pull up, as people do in gym, will the force on the bar increases? Since i am pulling up my weight, will the weight or force on the bar doubles?
Asked by ay567602 | 17 Dec, 2020, 02:36: AM
Free body diagram of a person hanging in the bar is shown in above figure.
Mass of the person is m and weight mg is acting downward.
Tension force T is applied through hands and this equal tension force T is pulling the bar .

If the person is just hanging without making any movement , then T = mg .
Hence if there is no movement , pulling force T equals weight of person .

If the person is pulling up and making accelerated motion upward with acceleration a ,
then by applying Newton's second law, we have

T - mg = ma   or   T = m(g+a)

Hence as seen by above equation , pulling force of bar , that is tension force increases.
If acceleration equals to acceleration due to gravity , then pulling force T doubles.

If the person is pulling up with uniform speed , then a = 0 and tension force of pulling force of bar just equals his weight
Answered by Thiyagarajan K | 17 Dec, 2020, 10:44: AM

## Concept Videos

CBSE 12-science - Physics
Asked by nikstar1456 | 14 Feb, 2024, 01:09: PM
CBSE 12-science - Physics
Asked by rameshsanju123 | 08 Feb, 2024, 08:45: PM
CBSE 12-science - Physics
Asked by murshidibrahimkk | 08 Feb, 2024, 10:28: AM
CBSE 12-science - Physics
Asked by sunnyk67422 | 08 Feb, 2024, 07:11: AM
CBSE 12-science - Physics
Asked by sachin.sondur2012 | 07 Feb, 2024, 11:26: AM
CBSE 12-science - Physics
Asked by patelnamra608 | 26 Jan, 2024, 11:01: AM