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CBSE Class 12-science Answered

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Asked by indrajitchatterjee22092002 | 04 Aug, 2020, 10:11: PM
answered-by-expert Expert Answer
To find the integral of 1/sqrt{x^2 - ax}
Let space straight I equals integral fraction numerator dx over denominator square root of straight x squared minus ax end root end fraction Take space straight x equals asin squared straight theta rightwards double arrow dx equals 2 straight a space sinθ space cosθ space dθ straight I equals integral fraction numerator 2 straight a space sinθ space cosθ space dθ over denominator square root of straight a squared sin to the power of 4 straight theta minus straight a squared sin squared straight theta end root end fraction equals integral fraction numerator 2 straight a space sinθ space cosθ space dθ over denominator asinθ square root of 1 minus sin squared straight theta end root end fraction equals integral fraction numerator 2 space cosθ space dθ over denominator cosθ end fraction equals integral 2 dθ equals 2 straight theta equals 2 asin squared straight theta
Answered by Renu Varma | 05 Aug, 2020, 11:52: AM

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CBSE 12-science - Maths
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