CBSE Class 12-science Answered
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Asked by indrajitchatterjee22092002 | 04 Aug, 2020, 22:11: PM
To find the integral of 1/sqrt{x^2 - ax}
![Let space straight I equals integral fraction numerator dx over denominator square root of straight x squared minus ax end root end fraction
Take space straight x equals asin squared straight theta
rightwards double arrow dx equals 2 straight a space sinθ space cosθ space dθ
straight I equals integral fraction numerator 2 straight a space sinθ space cosθ space dθ over denominator square root of straight a squared sin to the power of 4 straight theta minus straight a squared sin squared straight theta end root end fraction
equals integral fraction numerator 2 straight a space sinθ space cosθ space dθ over denominator asinθ square root of 1 minus sin squared straight theta end root end fraction
equals integral fraction numerator 2 space cosθ space dθ over denominator cosθ end fraction
equals integral 2 dθ
equals 2 straight theta
equals 2 asin squared straight theta](https://images.topperlearning.com/topper/tinymce/cache/eff66e038db11ce972c31f8ba8f5cb49.png)
Answered by Renu Varma | 05 Aug, 2020, 11:52: AM
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