JEE Class main Answered
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Asked by adjacentcalliber10 | 12 May, 2019, 15:27: PM
Expert Answer
we can see the function (sin2x-sinx-1) graph(bold line)
and sgn(sin2x-sinx-1) graph(dotted line)
the signum function has 2 points of discontinuity in 0 to 2pi range
so 4 points in 0 to 4pi range
but even 0 to 5pi range it will still have 4 points of discontinuity
hence option (3), n will have two values for 4 point of discontinuity, 4 and 5
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