CBSE Class 10 Answered
solve:-
Asked by Abhishek Kumar Singh | 16 Oct, 2013, 12:16: PM
Expert Answer
abx2-(a+b)2(x-1)=0
abx2-(a+b)2x+(a+b)2=0
Using quadratic formula,
B2-4AC=(a+b)4-4ab(a+b)2
=(a+b)2[(a+b)2-4ab]
=(a+b)2(a2+b2+2ab-4ab)
=(a+b)2(a-b)2
So, sqrt (B2-4AC)=
(a+b)(a-b) =(a2-b2)
x=[(a+b)2 (a2-b2)]/2ab
x=[a2+b2+2ab(a2-b2)]/2ab
x=(a+b)/b or x=(a+b)/a
Answered by | 16 Oct, 2013, 12:29: PM
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