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Solve
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Asked by sarveshvibrantacademy | 12 May, 2019, 14:20: PM
answered-by-expert Expert Answer
begin mathsize 16px style limit as straight n rightwards arrow infinity of space fraction numerator straight x to the power of straight n minus sinx to the power of straight n over denominator straight x to the power of straight n plus sinx to the power of straight n end fraction equals limit as straight n rightwards arrow infinity of space fraction numerator 1 minus begin display style sinx to the power of straight n over straight x to the power of straight n end style over denominator 1 plus sinx to the power of straight n over straight x to the power of straight n end fraction equals 1 straight f left parenthesis straight x right parenthesis space has space straight a space removable space type space of space discontinuity space at space straight x equals 1. end style
Answered by Sneha shidid | 15 May, 2019, 10:43: AM
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