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Asked by sarveshvibrantacademy | 12 May, 2019, 02:20: PM
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begin mathsize 16px style limit as straight n rightwards arrow infinity of space fraction numerator straight x to the power of straight n minus sinx to the power of straight n over denominator straight x to the power of straight n plus sinx to the power of straight n end fraction equals limit as straight n rightwards arrow infinity of space fraction numerator 1 minus begin display style sinx to the power of straight n over straight x to the power of straight n end style over denominator 1 plus sinx to the power of straight n over straight x to the power of straight n end fraction equals 1 straight f left parenthesis straight x right parenthesis space has space straight a space removable space type space of space discontinuity space at space straight x equals 1. end style
Answered by Sneha shidid | 15 May, 2019, 10:43: AM
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⭕ question No. 84 , plz explain in detail !!
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Asked by sawantsb765 | 01 Jun, 2019, 08:39: PM
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solve
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Asked by sarveshvibrantacademy | 17 May, 2019, 09:46: AM
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JEE main - Maths
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Asked by sarveshvibrantacademy | 17 May, 2019, 09:31: AM
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JEE main - Maths
solve
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Asked by sarveshvibrantacademy | 17 May, 2019, 09:18: AM
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JEE main - Maths
Solve
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Asked by sarveshvibrantacademy | 15 May, 2019, 11:25: AM
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JEE main - Maths
Solve
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Asked by adjacentcalliber10 | 12 May, 2019, 03:27: PM
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JEE main - Maths
Solve
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Asked by adjacentcalliber10 | 12 May, 2019, 03:21: PM
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