Request a call back

Join NOW to get access to exclusive study material for best results

JEE Class main Answered

solve
question image
Asked by sarveshvibrantacademy | 30 Apr, 2019, 12:25: PM
answered-by-expert Expert Answer
The deviation in prism is given by
delta equals i plus e minus A
where
i= angle of incidence
e= angle of emergence
A = angle of prism or refracting angle
 
therefore,
42 to the power of omicron equals 2 i minus 56 to the power of omicron
i equals 49 to the power of omicron
Answered by Utkarsh Lokhande | 30 Apr, 2019, 12:56: PM
JEE main - Physics
Asked by kunalauditore94 | 21 Aug, 2024, 19:13: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by sreelekhachakali2006 | 15 Mar, 2024, 10:35: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by ramanjaneyuluoguru | 22 Jan, 2024, 12:30: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by kumarpurshotam451 | 29 Sep, 2023, 15:46: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by swayamagarwal2114 | 15 Jul, 2022, 09:19: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by swayamagarwal2114 | 15 Jul, 2022, 09:18: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
JEE main - Physics
Asked by 3047-manvir | 05 Jul, 2022, 12:09: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT