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Asked by sarveshvibrantacademy | 03 May, 2019, 10:45: AM
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Lets assume that refraction takes place at boundary
Therefore,
mu subscript 1 S i n theta subscript 1 equals mu subscript 2 S i n theta subscript 2 2 cross times S i n 45 equals mu subscript 2 S i n theta subscript 2 mu subscript 2 S i n theta subscript 2 equals square root of 2 S i n theta subscript 2 equals fraction numerator square root of 2 over denominator mu subscript 2 end fraction S o space h e r e space w e space c a n space s a y space t h a t space square root of 2 less than mu subscript 2 less than infinity 0 less than S i n theta subscript 2 less than 1 0 to the power of 0 less than theta subscript 2 less than 90 to the power of 0 I n space t h i s space c a s e space t h e space t o t a l space d e v i a t i o n space w o u l d space b e delta less than 45 to the power of 0
But it is not given in any option
 
Now
0 less than mu subscript 2 less than square root of 2 t h e n S in theta equals fraction numerator square root of 2 over denominator mu subscript 2 end fraction N o t space p o s s i b l e space a s space sin theta space c a n space n o t space b e space g r e a t e r space t h a n space 1 I f space mu subscript 2 less than square root of 2 t h e n space t o t a l space i n t e r n a l space r e l e c t i o n space t a k e s space p l a c e space T o t a l space d e v i a t i o n space w o u l d space b e delta equals 180 minus 2 cross times 45 to the power of 0 delta equals 90 to the power of 0
Answered by Utkarsh Lokhande | 03 May, 2019, 12:50: PM
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