solve this

 

Asked by cikugogoi1999 | 31st Jul, 2019, 12:37: PM

Expert Answer:

Que. (K)
 
Calculate the number of atoms in each of the following:
(a) 0.4 mole of nitrogen
(b) 1.4 gm of sulphur
 
(a) 0.4 mole nitrogen
 
      We know,
No. of atoms = No. of moles × Avogadro's number
 
                      = 0.4 × 6.022×1023 
 
No. of atoms = 2.4088 ×1023 
 
(b) 1.6 gm of sulphur
 
     No. of atoms = No. of moles × Avogadro's number
 
     Molarmass of sulphur = 32
 
     No. of moles of sulphur =
 
     equals fraction numerator 1.6 over denominator 32 end fraction

equals 0.05 space mol
 
  No. of atoms =  0.05 × 6.022×1023 
 
  No. of atoms = 3.011 ×1022 
 
 
      

Answered by Varsha | 2nd Aug, 2019, 11:12: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.