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Solve this problem y
Asked by sanjaysingh.srct | 12 Aug, 2019, 09:48: AM
Expert Answer
Minimum value of |2x-1| = 0
Maximum value of |2x-1| = infinity
now 
[0]=0
[infinity]= not defined
Answered by Arun | 19 Aug, 2019, 11:06: AM
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JEE main - Maths
Q) Find the range of f(x) = x + 1/x Ans) See the image which I have uploaded.. I have just broken the eqn into √x² + 1/√x² +2 -2 ..and have formed the identity (a+b)² and the range is coming  (-∞, 2 ] U [ -2, ∞ ) which is wrong.. the correct range is coming from (a-b)² which is (-∞, -2 ] U [ 2, ∞ ). My Doubt- Why (a+b)² is not giving the correct range? Request- Please send the solution using (a+b)². I've attached an image and let me know if I'm wrong somewhere or why the correct solution isn't coming by using (a+b)². Thanks, Samit  Future Top 50 ranker in JEE ADVANCE
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JEE main - Maths
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