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Solve the equation (x+4)(x+7)(x+8)(x+11)+20=0
Asked by tdp8800 | 29 Apr, 2020, 07:19: AM Expert Answer
(x+4)(x+7)(x+8)(x+11)+20=0
(x+4)(x+11)(x+8)(x+7)+20=0
(x2+15x+44)(x2+15x+56)+20=0 ... (i)
Let y=x2+15x ... (ii)
(y+44)(y+56)+20=0
y2+100y+2464=0
y2+54y+46y+2484=0
y(y+54)+46(y+54)=0
(y+54)(y+46)=0
y=-54 or y=-46
Therefore,
x2+15x=-54 or x2+15x=-46
x2+15x+54=0 or x2+15x+46=0 Answered by Renu Varma | 29 Apr, 2020, 02:23: PM

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