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solve the below question
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Asked by sarveshvibrantacademy | 22 Mar, 2019, 15:35: PM
answered-by-expert Expert Answer
begin mathsize 16px style cos to the power of negative 1 end exponent square root of fraction numerator 1 plus cosx over denominator 2 end fraction end root equals cos to the power of negative 1 end exponent square root of fraction numerator 2 cos squared space begin display style straight x over 2 end style over denominator 2 end fraction end root space space space space space space space space space space space 1 plus cosx equals 2 cos squared space straight x divided by 2 equals cos to the power of negative 1 end exponent open parentheses cos straight x over 2 close parentheses equals straight x over 2 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space cos to the power of negative 1 end exponent left parenthesis cosx right parenthesis equals straight x space end style
Answered by Sneha shidid | 22 Mar, 2019, 16:45: PM
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JEE main - Maths
solve questions 19
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Asked by nehalhp04 | 27 May, 2024, 16:40: PM
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JEE main - Maths
.
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Asked by sandipan.sarma6 | 14 Apr, 2024, 10:27: AM
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JEE main - Maths
some
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Asked by pranavpatil7386 | 07 Feb, 2024, 20:54: PM
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JEE main - Maths
if cot^-(-cot5x)=tan^-( cotx),0
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JEE main - Maths
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JEE main - Maths
cos x=-1/2,x lies in which quadrant
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JEE main - Maths
tan tita+sec tita -1/tan tita-sec tita+1
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JEE main - Maths
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Asked by indukurinishita54 | 07 Jun, 2021, 19:16: PM
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JEE main - Maths
plese solve it in detail with step by step explanation  
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Asked by ashwinbalaaji30 | 18 May, 2021, 10:51: AM
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JEE main - Maths
2.
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Asked by Premnerusu37 | 02 Aug, 2020, 07:32: AM
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