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CBSE Class 10 Answered

solve q)41
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Asked by ajayrath7 | 11 Apr, 2019, 10:36: AM
answered-by-expert Expert Answer
begin mathsize 16px style Let space fraction numerator 1 over denominator 3 straight x space plus space straight y space end fraction equals space straight a space and space fraction numerator 1 over denominator 3 straight x space minus space straight y space end fraction equals space straight b comma space then space
straight a space plus space straight b space equals space 3 over 4 space space space... space left parenthesis straight i right parenthesis space space and space
1 half straight a space minus 1 half straight b space equals space space minus space 1 over 8 space space space
rightwards double arrow straight a space minus space straight b space equals negative space 1 fourth space space space space space.... space left parenthesis ii right parenthesis space
Adding space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis comma space we space get
2 straight a space equals space 1 half
rightwards double arrow straight a space equals space 1 fourth
Substitute space the space value space of space straight a space in space equation space left parenthesis straight i right parenthesis comma space we space get
straight b space equals space 1 half
rightwards double arrow fraction numerator 1 over denominator 3 straight x space plus space straight y space end fraction equals space 1 fourth space and space fraction numerator 1 over denominator 3 straight x space minus space straight y space end fraction equals space 1 half
rightwards double arrow 3 straight x space plus space straight y space equals space 4 space space space.... space left parenthesis iii right parenthesis space and space
3 straight x space minus space straight y space equals space 2 space space.... space left parenthesis iv right parenthesis
Adding space left parenthesis iii right parenthesis space and space left parenthesis iv right parenthesis comma space we space get
6 straight x space equals space 6
rightwards double arrow straight x space equals space 1
Put space straight x space equals space 1 space in space equation space left parenthesis iii right parenthesis comma space we space get
3 left parenthesis 1 right parenthesis space plus space straight y space equals space 4
rightwards double arrow straight y space equals space 1
Hence space the space solution space is space straight x space equals space 1 space and space straight y space equals space 1.

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Answered by Yasmeen Khan | 11 Apr, 2019, 11:24: AM
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